Answer with Explanation:

We may have (3 men and 2 women) or (4 men and 1 woman) or (5 men only).

 Required number of ways = (7C3 x 6C2) + (7C4 x 6C1) + (7C5)
 
 = ( 7 x 6 x 5 /3 x 2 x 1) x( 6 x 5 / 2 x 1 ) + (7C3 x 6C1) + (7C2) 
 
 = 525 +( 7 x 6 x 5 /3 x 2 x 1  x 6 ) + ( 7 x 6 / 2 x 1 )  

 = (525 + 210 + 21) 

 = 756. 

 
 

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