Answer with Explanation:
(Sq root of x -1/Sq root of x )2 = x + 1/x -2
= (3 + 2 Sq root 2) + 1 / ( 3 + 2 Sq root 2) - 2
= (3 + 2 Sq root 2) + 1/ (3 + 2 Sq root 2)x = (3 - 2 Sq root 2) / (3 - 2 Sq root 2) -2
= (3 + 2 Sq root 2) + (3 - 2 Sq root 2) - 2
= 4.
Therefore,(Sq root x - 1/ Sq root x) = 2.
(Sq root of x -1/Sq root of x )2 = x + 1/x -2
= (3 + 2 Sq root 2) + 1 / ( 3 + 2 Sq root 2) - 2
= (3 + 2 Sq root 2) + 1/ (3 + 2 Sq root 2)x = (3 - 2 Sq root 2) / (3 - 2 Sq root 2) -2
= (3 + 2 Sq root 2) + (3 - 2 Sq root 2) - 2
= 4.
Therefore,(Sq root x - 1/ Sq root x) = 2.