Answer with Explanation:
Total number of balls = (2 + 3 + 2) = 7.
Let S be the sample space.
Then, n(S) = Number of ways of drawing 2 balls out of 7
= 7C2
= (7 x 6) / (2 x 1)
= 21.
Let E = Event of drawing 2 balls, none of which is blue.
n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls.
= 5C2
= (5 x 4)/(2 x 1)
= 10.
Therefore, P(E) = n(E)/n(S) = 10/21 .
Total number of balls = (2 + 3 + 2) = 7.
Let S be the sample space.
Then, n(S) = Number of ways of drawing 2 balls out of 7
= 7C2
= (7 x 6) / (2 x 1)
= 21.
Let E = Event of drawing 2 balls, none of which is blue.
n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls.
= 5C2
= (5 x 4)/(2 x 1)
= 10.
Therefore, P(E) = n(E)/n(S) = 10/21 .