__SOLVED SELECTED QUESTIONS ON__

" PROBLEMS ON AGES "

" PROBLEMS ON AGES "

" PROBLEMS ON AGES "

A. 45 B. 40 C. 35 D. 30

Answer : Option C

Explanation :

Let the present age of P and Q be 3x and 4x respectively.

Ten years ago, P was half of Q's age

=> (3x – 10) = 12(4x – 10)

=> 6x – 20 = 4x – 10

=> 2x = 10

=> x = 5

Total of their present ages = 3x + 4x = 7x = 7 × 5 = 35

A. 4 times B. 4 times C. 2 times D. 3 times

Answer : Option C

Explanation :

Assume that Sunil's present age = x.

Then father's present age = 3x + x = 4x

After 8 years, father's age = 212 times of Sunils' age

=> (4x+8) = 212(x+8)

=> 4x + 8 = 52(x + 8)

=> 8x + 16 = 5x + 40

=> 3x = 40 - 16 = 24

=> x = 243 = 8

After further 8 years,

Sunil's age = x + 8 + 8 = 8 + 8 + 8 = 24

Father's age = 4x + 8 + 8 = 4 × 8 + 8 + 8 = 48

A. 70 B. 60 C. 50 D. 40

Answer : Option C

Explanation :

Let the age before 10 years = x

Then 125x100 = x + 10

=>125x = 100x + 1000

=> x = 100025 = 40

Present age = x + 10 = 40 +10 = 50

A. 23 years B. 22 years C. 21 years D. 20 years

Answer : Option B

Explanation :

Let the present age of the son = x years

Then present age the man = (x+24) years

Given that in 2 years, man's age will be twice the age of his son

=> (x+24) +2 = 2(x+2)

=> x = 22

A. 28 B. 27 C. 26 D. 24

Answer : Option D

Explanation :

Ratio of the present age of Kiran and Syam = 5 : 4

Let the present age of Kiran = 5x

Present age of Syam = 4x

After 3 years, ratio of their ages = 11:9

=> (5x + 3) : (4x + 3) = 11 : 9

=> 9(5x + 3) = 11(4x + 3)

=> 45x + 27 = 44x + 33

=> x = 33-27 =6

Syam's present age = 4x = 4×6 = 24

A. 6 years B. 5 years C. 4 years D. 3 years

Answer : Option C

Explanation :

Let the age of the youngest child = x

Then the ages of 5 children can be written as x, (x+3), (x+6),(x+9) and (x+12)

x + (x+3) + (x+6) + (x+9) + (x+12) = 50

=> 5x + 30 = 50

=> 5x = 20

=> x = 205 = 4

A. 10 B. 9 C. 8 D. 7

Answer : Option A

Explanation :

Let the age of C = x. Then

Age of B = 2x

Age of A = 2 + 2x

The total age of A,B and C =27

=> (2+2x) + 2x + x = 27

=> 5x = 25

=> x = 255 = 5

B's age = 2x = 2×5 = 10

A. 48 B. 45 C. 43 D. 44

Answer : Option D

Explanation :

Total age of all students = 22×21

Total age of all students + age of the teacher = 23 × 22

Age of the teacher = 23×22 – 22×21 = 22(23-21) = 22×2 = 44

A. 20 years B. 18 years C. 14 years D. 22 years

Answer : Option C

Explanation :

Let the son's present age be x years.

Then, (38 - x) = x

=> 2x = 38

=> x = 382 = 19

Son's age 5 years back = 19-5 = 14

A. 10 years B. 12 years C. 8 years D. 5 years

Answer : Option D

Explanation :

Consider Ayisha's present age = x

Then her father's age = 6x

Given that Ayisha 's father's age will be twice the age of Shankar's age after 10 years

=> Shankar's age after 10 years = 12(6x + 10) = 3x + 5

Also given that Shankar's eight birthdays was celebrated two years before

=> Shankar's age after 10 years = 8 + 12 = 20

=> 3x + 5 = 20

=> x = 153 = 5

Therefore, Ayisha 's present age = 5 years

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